Download e-book for iPad: Instructor’s Solutions Manual of College Algebra And by Richard N. Aufmann

By Richard N. Aufmann

ISBN-10: 0618825088

ISBN-13: 9780618825080

ISBN-10: 0618825207

ISBN-13: 9780618825202

Includes entire options to all odd-numbered difficulties within the textual content, in addition to learn assistance and a tradition checks for every bankruptcy; textual content particular.

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Extra info for Instructor’s Solutions Manual of College Algebra And Trigonometry

Example text

12 + x = 5 x − 7 + 2 3 −4 ⎛ 5x − 7 + 2 ⎞ 12 x + ⎛ ⎞ 12 ⋅ ⎜ ⎟ = 12 ⋅ ⎜ ⎟ ⎝ −4 ⎠ ⎝ 3 ⎠ −3(12 + x ) = 4(5 x − 7) + 24 −36 − 3x = 20 x − 28 + 24 −36 − 3x = 20 x − 4 −3x − 20 x = −4 + 36 −23x = 32 x = − 32 23 23. −3( x − 5) = −3x + 15 24. 2 x + 1 = 6x + 1 3 3 1 ⎛ ⎞ ⎛ 3 ⋅ ⎜ 2 x + ⎟ = 3 ⋅ ⎜ 6 x + 1 ⎟⎞ 3⎠ ⎝ ⎝ 3 ⎠ 6x + 1 = 6x + 1 Identity 25. 2 x + 7 = 3( x − 1) 2 x + 7 = 3x − 3 2 x − 3x = −3 − 7 − x = −10 x = 10 Conditional equation 4[2 x − 5( x − 3)] = 6 4[2 x − 5 x + 15] = 6 4[ −3x + 15] = 6 −12 x + 60 = 6 −12 x = −54 x=9 2 Conditional equation 27.

00 48. 00 4 14 7 or 24 12 15 14 7 or 24 12 x 18 3 or 24 4 15 + x 18 3 or 24 4 4+x x + 7 (15) = 3 (15 + x ) 12 4 7 ⎡ ⎤ 12 ⋅ x + (15) = 12 ⋅ ⎡ 3 (15 + x ) ⎤ ⎢⎣ ⎥⎦ ⎢⎣ 4 ⎥⎦ 12 12 x + 7(15) = 9(15 + x ) 12 x + 105 = 135 + 9 x 3x = 30 x = 10 4 + 7 x = 3 (4 + x ) 12 4 7 ⎡ ⎤ 12 ⋅ 4 + x = 12 ⋅ ⎡ 3 (4 + x ) ⎤ ⎢⎣ 12 ⎥⎦ ⎢⎣ 4 ⎥⎦ 48 + 7 x = 9(4 + x ) 48 + 7 x = 36 + 9 x −2 x = −12 x=6 10 g of pure gold 6 oz of 14 karat gold Copyright © Houghton Mifflin Company. All rights reserved. 46 49. Chapter 1: Equations and Inequalities Let t = the time it takes both electricians working together to wire the house.

I 97 = i1 = i Copyright © Houghton Mifflin Company. All rights reserved. 1 1. 5. 8. 2 x + 10 = 40 2 x = 40 − 10 2 x = 30 x = 15 −3 y + 20 = 2 2. y=6 2( x − 3) − 5 = 4( x − 5) 2 x − 6 − 5 = 4 x − 20 2 x − 11 = 4 x − 20 2 x − 4 x = −20 + 11 −2 x = −9 x=9 2 6. 6(5s − 11) − 12(2 s + 5) = 0 30s − 66 − 24 s − 60 = 0 6s − 126 = 0 9. 6s = 126 s = 126 6 s = 21 11. 3. −3 y = 2 − 20 −3 y = −18 5 x + 2 = 2 x − 10 5 x − 2 x = −10 − 2 3x = −12 x = −4 5( x − 4) − 7 = −2( x − 3) 5 x − 20 − 7 = −2 x + 6 5 x − 27 = −2 x + 6 5 x + 2 x = 6 + 27 7 x = 33 x = 33 7 7.

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Instructor’s Solutions Manual of College Algebra And Trigonometry by Richard N. Aufmann


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